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Transformer Calculations

Reviewed August 23, 2026

In learning paths: Master Electrician Exam Prep

Assumes you know: How Transformers Work

Transformer calculations all descend from one identity: power in equals power out. A transformer trades voltage for current at a fixed ratio, so kVA stays the same on both windings while volts and amps swap places. Every sizing task, primary conductors, secondary conductors, protection, is this one identity plus a table lookup.

Why it matters on the job

Transformers are where systems change voltage, 480 V distribution down to 208Y/120 V for receptacles and lighting, and each side needs conductors and protection sized to its own current. The currents differ by the turns ratio, so a mistake here is never small: confuse the sides and you are wrong by a factor of two or more.

The formulas

Single-phase: current = (kVA × 1,000) ÷ volts.

Three-phase: current = (kVA × 1,000) ÷ (volts × 1.732), where volts is line-to-line and 1.732 is √3.

Work each winding independently at its own voltage. The kVA is the same number both times; only the voltage changes, and the current follows.

Protection comes from your code book’s transformer table. The everyday case for 600 V and under: with protection in both primary and secondary, the secondary device at up to 125 % of secondary current, with the primary device then allowed up to 250 %; with primary-only protection, the primary device at up to 125 % of primary current. Where 125 % misses a standard rating, the next size up is permitted.

Worked example

A 75 kVA three-phase transformer steps 480 V down to 208Y/120 V.

  1. Primary current: 75,000 ÷ (480 × 1.732) = 75,000 ÷ 831.4 = 90.2 A.
  2. Secondary current: 75,000 ÷ (208 × 1.732) = 75,000 ÷ 360.3 = 208.2 A.
  3. Same 75 kVA, both sides: 831.4 × 90.2 ≈ 360.3 × 208.2 ≈ 75,000. The identity checks.
  4. Secondary conductors must carry 208.2 A: from the 75 °C copper column, 4/0 AWG at 230 A.
  5. Secondary protection at 125 %: 208.2 × 1.25 ≈ 260 A → next standard size, a 300 A device is permitted; many designs choose 250 A and load accordingly.

A single-phase check, no √3: a 25 kVA transformer, 480 V to 240 V. Primary: 25,000 ÷ 480 = 52.1 A. Secondary: 25,000 ÷ 240 = 104.2 A. Halve the voltage, double the current.

A transformer drawn as two coils, the left labeled 480 volts and 90 amps, the right labeled 208 volts and 208 amps, with same 75 kVA written between them

The kVA never changes sides: what the voltage gives up, the current takes

Where it bites

  • A handy coincidence, not a law: at 208 V three-phase, amps ≈ kVA × 2.78, which is why a 75 kVA transformer lands near 208 A. Use it to sanity-check, but show the real division on paper and on exams.
  • Line-to-line voltage goes in the three-phase formula. Using 120 V because the secondary serves 120 V loads inflates the current by 1.732. The wye’s 120 V is line-to-neutral; the formula wants 208.
  • Transformer protection does not protect the secondary conductors. Secondary conductors get their own protection rules, and the 10-foot and 25-foot tap rules usually govern the run to the first panel. Sizing wire to the transformer’s primary breaker is the classic miss.
  • Inrush is real here too. Energizing a transformer draws a magnetizing surge, which is why the table tolerates generous primary percentages. A primary device sized tight to 100 % will nuisance-trip on energization.

Exam relevance

Transformer current is among the most reliable calculation questions on master exams and common on journeyman ones: given kVA and voltages, find primary or secondary current, then a conductor or device. The marks are lost on √3, on grabbing line-to-neutral voltage, and on solving the wrong side. Write both currents down first, every time; the rest of the problem is table lookups.

Verified requirements

WhereExpiresRenewalContinuing education
TexasYes1 year4 hours per annual renewal cycle

Verified against the issuing authority; see sources below. Always confirm current rules with the authority before acting.